? AFTER
: BEFORE);
insert_con_into(con, target, position);
- } else if (con->parent->parent->type == CT_WORKSPACE &&
+ } else if (!next &&
+ con->parent->parent->type == CT_WORKSPACE &&
con->parent->layout != L_DEFAULT &&
con_num_children(con->parent) == 1) {
/* Con is the lone child of a non-default layout container at the edge
--- /dev/null
+#!perl
+# vim:ts=4:sw=4:expandtab
+#
+# Please read the following documents before working on tests:
+# • http://build.i3wm.org/docs/testsuite.html
+# (or docs/testsuite)
+#
+# • http://build.i3wm.org/docs/lib-i3test.html
+# (alternatively: perldoc ./testcases/lib/i3test.pm)
+#
+# • http://build.i3wm.org/docs/ipc.html
+# (or docs/ipc)
+#
+# • http://onyxneon.com/books/modern_perl/modern_perl_a4.pdf
+# (unless you are already familiar with Perl)
+#
+# Tests that windows inside containers with a single child do not jump
+# over other containers and erratically move across outputs.
+# Ticket: #2466
+# Bug still in: 4.14-63-g75d11820
+use i3test i3_config => <<EOT;
+# i3 config file (v4)
+font -misc-fixed-medium-r-normal--13-120-75-75-C-70-iso10646-1
+
+fake-outputs 640x480+0+0,640x480+640+0
+
+workspace left output fake-0
+workspace right output fake-1
+EOT
+
+cmd 'workspace right';
+
+# ┌───────────────────────────┐ ┌───────────────────────────┐
+# │ Output 1 │ │ Output 2 - splith │
+# │ │ │┌───────────┐┌────────────┐│
+# │ │ ││ ││ splitv ││
+# │ │ ││ ││╔══════════╗││
+# │ │ ││ ││║ ║││
+# │ (empty workspace) │ ││ first ││║ second ║││
+# │ │ ││ ││║ ║││
+# │ │ ││ ││║ ║││
+# │ │ ││ ││╚══════════╝││
+# │ │ │└───────────┘└────────────┘│
+# └───────────────────────────┘ └───────────────────────────┘
+#
+# Moving "second" left shouldn't cause it to jump over to output 1.
+
+my $first = open_window;
+my $second = open_window;
+
+# Put the second window into its own splitv container
+cmd 'split v';
+
+is_num_children('left', 0, 'No children on left');
+is_num_children('right', 2, 'Two children on right');
+
+# Move the second window to the left
+cmd 'move left';
+
+is_num_children('left', 0, 'Still no children on left');
+is_num_children('right', 2, 'Still two children on right');
+
+done_testing;