x86: pci: Do not assign irq 0 to pci device

[u-boot] / arch / x86 / cpu / pci.c

diff --git a/arch/x86/cpu/pci.c b/arch/x86/cpu/pci.c
index e23b233961cec277154b22941565990af7c87cab..f8da08035e62bbcfd5454682bfa5b03fbeca19a9 100644 (file)
--- a/arch/x86/cpu/pci.c
+++ b/arch/x86/cpu/pci.c
@@ -151,3 +151,33 @@ int pci_x86_write_config(struct udevice *bus, pci_dev_t bdf, uint offset,
 
        return 0;
 }
+
+void pci_assign_irqs(int bus, int device, u8 irq[4])
+{
+       pci_dev_t bdf;
+       int func;
+       u16 vendor;
+       u8 pin, line;
+
+       for (func = 0; func < 8; func++) {
+               bdf = PCI_BDF(bus, device, func);
+               vendor = x86_pci_read_config16(bdf, PCI_VENDOR_ID);
+               if (vendor == 0xffff || vendor == 0x0000)
+                       continue;
+
+               pin = x86_pci_read_config8(bdf, PCI_INTERRUPT_PIN);
+
+               /* PCI spec says all values except 1..4 are reserved */
+               if ((pin < 1) || (pin > 4))
+                       continue;
+
+               line = irq[pin - 1];
+               if (!line)
+                       continue;
+
+               debug("Assigning IRQ %d to PCI device %d.%x.%d (INT%c)\n",
+                     line, bus, device, func, 'A' + pin - 1);
+
+               x86_pci_write_config8(bdf, PCI_INTERRUPT_LINE, line);
+       }
+}