Makefile: Suppress output of python libfdt build command

This should not be printed by default. Prefix it with $(Q).

Fixes ee95d10b: ("fdt: Build the new python libfdt module")
Signed-off-by: Bin Meng <bmeng.cn@gmail.com>

diff --git a/tools/Makefile b/tools/Makefile
index 5605fa7c8d3166ecceab7b072df3fc3d8b4cef7a..a0db19d6b057394d5c3872dd203c854a46f2faed 100644 (file)
--- a/tools/Makefile
+++ b/tools/Makefile
@@ -131,8 +131,8 @@ fit_check_sign-objs   := $(dumpimage-mkimage-objs) fit_check_sign.o
 # all three files in $(obj)/tools: _libfdt.so, libfdt.py and libfdt_wrap.c
 # The latter is a temporary file which we could actually remove.
 tools/_libfdt.so: $(LIBFDT_SRCS) $(LIBFDT_SWIG)
-       cp $(LIBFDT_SWIG) tools/.
-       unset CC; \
+       $(Q)cp $(LIBFDT_SWIG) tools/.
+       $(Q)unset CC; \
        unset CROSS_COMPILE; \
        LDFLAGS="$(HOSTLDFLAGS)" CFLAGS= VERSION="u-boot-$(UBOOTVERSION)" \
                CPPFLAGS="$(_hostc_flags)" OBJDIR=tools \